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Rules Discussion / Low health creature with burns receives freeze tokens - will it die?
« on: September 04, 2019, 06:14:15 PM »
What happens
If a living creature has 10 health with 6 damage and 2 burn conditions on it when it receives 2 freeze conditions from beam of frost.
From the codex elementalist:
A creature with Freeze conditions rolls 1 less die on non-spell attacks. At the end of a creature’s activation, remove 1 Freeze condition from them, if possible. Each Freeze condition on a living creature is also considered 2 damage that cannot be healed. If there are ever Freeze conditions on an object with Burn conditions, remove 1 of each. Repeat this process until there are only Freeze or Burn markers remaining. This is a frost condition and has a removal cost of 2. In Arena, Freeze also grants the Lumbering trait to the affected creature.
So in step 6 of the attack sequence (damage and effects) the freezes are added.
This should kill the creature right here and now before we start removing 1 of each (burn/freeze).
Is this correct? Also i'm wondering if this is intended or not.
If a living creature has 10 health with 6 damage and 2 burn conditions on it when it receives 2 freeze conditions from beam of frost.
From the codex elementalist:
A creature with Freeze conditions rolls 1 less die on non-spell attacks. At the end of a creature’s activation, remove 1 Freeze condition from them, if possible. Each Freeze condition on a living creature is also considered 2 damage that cannot be healed. If there are ever Freeze conditions on an object with Burn conditions, remove 1 of each. Repeat this process until there are only Freeze or Burn markers remaining. This is a frost condition and has a removal cost of 2. In Arena, Freeze also grants the Lumbering trait to the affected creature.
So in step 6 of the attack sequence (damage and effects) the freezes are added.
This should kill the creature right here and now before we start removing 1 of each (burn/freeze).
Is this correct? Also i'm wondering if this is intended or not.